9x^2-80x-9=0

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Solution for 9x^2-80x-9=0 equation:



9x^2-80x-9=0
a = 9; b = -80; c = -9;
Δ = b2-4ac
Δ = -802-4·9·(-9)
Δ = 6724
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6724}=82$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-80)-82}{2*9}=\frac{-2}{18} =-1/9 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-80)+82}{2*9}=\frac{162}{18} =9 $

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